超新手的问题。。估计是语法
Ta的回复 ：xmlhttp.open("POST"," https://aip.baidubce.com/rest/2.0/ocr/v1/general?access_token="+apikey secretkey获取到的token,true); xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded"); xmlhttp.send("url= http://xxx.jpg"); 晚上试下，感谢“java-小帅、”
